## Elementary Algebra

We square both sides of the equation and solve. Thus: $\sqrt{2n-1} = 3 - \sqrt{ n -5} \\ 2n -1 = 9 +n -5 - 6\sqrt{n-5} \\ n -5 = -6 \sqrt{n-5}\\ n^2 -10n + 25 = 36(n-5) \\ n^2 - 46n +205 = 0 \\(n-41) (n-5) \\ n=5$ Note, when 41 is plugged back in, it does not get a true statement, so it is not a solution.