## Elementary Algebra

$\dfrac{14\sqrt{x}}{x^3}$
Using the properties of radicals, the given expression, $\dfrac{14}{\sqrt{x^5}} ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{14}{\sqrt{x^5}}\cdot\dfrac{\sqrt{x}}{\sqrt{x}} \\\\= \dfrac{14\sqrt{x}}{\sqrt{x^6}} \\\\= \dfrac{14\sqrt{x}}{(\sqrt{x^3})^2} \\\\= \dfrac{14\sqrt{x}}{x^3} .\end{array} Note that all variables are assumed to represent positive real numbers.