#### Answer

$\dfrac{\sqrt{6}}{8}$

#### Work Step by Step

Recall, we are not allowed to have radicals in the denominator of a fraction. Using the properties of radicals, the given expression, $
\dfrac{\sqrt{3}}{\sqrt{32}}
,$ simplifies to
\begin{array}{l}\require{cancel}
\dfrac{\sqrt{3}}{\sqrt{32}}\cdot\dfrac{\sqrt{2}}{\sqrt{2}}
\\\\=
\dfrac{\sqrt{6}}{\sqrt{64}}
\\\\=
\dfrac{\sqrt{6}}{\sqrt{(8)^2}}
\\\\=
\dfrac{\sqrt{6}}{8}
.\end{array}