## Elementary Algebra

$\dfrac{5\sqrt{2x}}{2x}$
Using the properties of radicals, the given expression, $\dfrac{5}{\sqrt{2x}} ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{5}{\sqrt{2x}}\cdot\dfrac{\sqrt{2x}}{\sqrt{2x}} \\\\= \dfrac{5\sqrt{2x}}{2x} .\end{array} Note that all variables are assumed to represent positive real numbers.