Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 9 - Roots and Radicals - 9.3 - More on Simplifying Radicals - Problem Set 9.3 - Page 412: 33

Answer

$\dfrac{2\sqrt{15}}{5}$

Work Step by Step

Recall, we are not allowed to have radicals in the denominator of a fraction. Using the properties of radicals, the given expression, $ \dfrac{2\sqrt{3}}{\sqrt{5}} ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{2\sqrt{3}}{\sqrt{5}}\cdot\dfrac{\sqrt{5}}{\sqrt{5}} \\\\= \dfrac{2\sqrt{15}}{5} .\end{array}
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