Elementary Algebra

$\dfrac{2\sqrt{15}}{5}$
Recall, we are not allowed to have radicals in the denominator of a fraction. Using the properties of radicals, the given expression, $\dfrac{2\sqrt{3}}{\sqrt{5}} ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{2\sqrt{3}}{\sqrt{5}}\cdot\dfrac{\sqrt{5}}{\sqrt{5}} \\\\= \dfrac{2\sqrt{15}}{5} .\end{array}