Chapter 7 - Algebraic Fractions - 7.5 - Fractional Equations and Problem Solving - Problem Set 7.5 - Page 306: 41

$= \frac{40}{48}$

Let $x = $ the denominator $\frac{x-8}{x} = \frac{5}{6}$ 1. Cross multiply: $6(x-8) = 5(x)$ $6x - 48 = 5x$ $6x - 5x - 48 = 0$ $x - 48 = 0$ $x = 48$ 2. Substitute the variable into the original expression to find the fraction $= \frac{x-8}{x}$ $= \frac{48-8}{48}$ $= \frac{40}{48}$