## Elementary Algebra

$= \frac{40}{48}$
Let $x =$ the denominator $\frac{x-8}{x} = \frac{5}{6}$ 1. Cross multiply: $6(x-8) = 5(x)$ $6x - 48 = 5x$ $6x - 5x - 48 = 0$ $x - 48 = 0$ $x = 48$ 2. Substitute the variable into the original expression to find the fraction $= \frac{x-8}{x}$ $= \frac{48-8}{48}$ $= \frac{40}{48}$