## Elementary Algebra

$n = 8$
1. Multiply by $n$ on both sides to remove the fractions in the equation. $\frac{90-n}{n} = 10 + \frac{2}{n}$ $90-n = 10n + \frac{2n}{n}$ 2. Cancel out the $n$'s in the fraction $90-n = 10n + 2$ 3. Solve for $n$ $90 - n - 10n - 2 = 0$ $88 - 11n = 0$ $11(8 - n) = 0$ $8 -n = 0$ $-n = -8$ $n = 8$