## Elementary Algebra

$n = \frac{3}{4}$
1. Multiply by $n-1$ on both sides of the equation to obtain: $\frac{3}{n-1} + 4 = \frac{2}{n-1}$ $3 + 4(n-1) = 2$ 3. Expand and solve for $n$ $3 + 4n - 4 = 2$ $3 + 4n - 4 - 2 = 0$ $4n + 3 - 6 = 0$ $4n - 3 = 0$ $4n = 3$ $n = \frac{3}{4}$