## Elementary Algebra

$n = 6$
1. Multiply by $n$ on both sides of the equation to remove the fractions: $\frac{51-n}{n} = 7 + \frac{3}{n}$ $51-n = 7n + \frac{3n}{n}$ 2. Cancel out the $n$'s in the fraction: $51 - n = 7n + 3$ 3. Solve for $n$ $51 - n - 7n - 3 = 0$ $48 - 8n = 0$ $8(6 - n) = 0$ $6 - n = 0$ $-n = -6$ $n = 6$