Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 6 - Factoring, Solving Equations, and Problem Solving - Chapter 6 Test - Page 275: 19


{$-4, \frac{2}{3}$}

Work Step by Step

Using the rules of factoring trinomials to factor the polynomial, we obtain: $8-10x-3x^{2}=0$ $-3x^{2}-10x+8=0$ $3x^{2}+10x-8=0$ $3x^{2}-2x+12x-8=0$ $x(3x-2)+4(3x-2)=0$ $(3x-2)(x+4)=0$ Now, we equate the two factors to zero and solve: $(3x-2)(x+4)=0$ $(3x-2)=0$ or $(x+4)=0$ $x=\frac{2}{3}$ or $x=-4$ Therefore, the solution set is {$-4, \frac{2}{3}$}.
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