Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 6 - Factoring, Solving Equations, and Problem Solving - Chapter 6 Test - Page 275: 13



Work Step by Step

Since $4n$ is common to both the terms of the equation, we take it out as a common factor: $4n^{2}=32n$ $4n^{2}-32n=0$ $4n(n-8)=0$ Now, we equate all the factors to zero to solve the equation: $4n(n-8)=0$ $4n=0$ or $(n-8)=0$ $n=0$ or $n=8$ Therefore, the solution set is {$0,8$}.
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