Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 6 - Factoring, Solving Equations, and Problem Solving - Chapter 6 Test - Page 275: 21



Work Step by Step

Using the rules of factoring trinomials to factor the polynomial, we obtain: $25n^{2}-70n+49=0$ $25n^{2}-35n-35n+49=0$ $5n(5n-7)-7(5n-7)=0$ $(5n-7)(5n-7)=0$ Now, we equate the two factors to zero and solve: $(5n-7)(5n-7)=0$ $(5n-7)=0$ or $(5n-7)=0$ $n=\frac{7}{5}$ or $n=\frac{7}{5}$ Therefore, the solution set is {$\frac{7}{5}$}.
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