#### Answer

{$5,9$}

#### Work Step by Step

Since $(x-5)$ is common to both the terms of the equation, we take it out as a common factor:
$9(x-5)-x(x-5)=0$
$(x-5)(9-x)=0$
Now, we equate all of the factors to zero to solve the equation:
$(x-5)(9-x)=0$
$x-5=0$ or $9-x=0$
$x=5$ or $x=9$
Therefore, the solution set is {$5,9$}.