# Chapter 2 - Real Numbers - Chapter 2 Review Problem Set - Page 88: 42

$= \frac{41n}{20}$

#### Work Step by Step

1) Find a common denominator in Step #2: multiply the first fraction by $20$, the second fraction by $5$, the third fraction by $20$, and the fourth fraction by $4$ to obtain a common denominator of $20$ $n - \frac{3}{4}n + 2n - \frac{1}{5}n$ $= \frac{n}{1} - \frac{3}{4}n + \frac{2n}{1} - \frac{1}{5}n$ (Rewrite the expression with fractions) $= \frac{n(20)}{20} - \frac{3n(5)}{20} + \frac{2n(20)}{20} - \frac{n(4)}{20}$ $= \frac{20n}{20} - \frac{15n}{20} + \frac{40n}{20} - \frac{4n}{20}$ $= \frac{20n-15n+40n-4n}{20}$ $= \frac{5n+40n-4n}{20}$ $= \frac{45n-4n}{20}$ $= \frac{41n}{20}$

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