## Elementary Algebra

Published by Cengage Learning

# Chapter 2 - Real Numbers - Chapter 2 Review Problem Set: 24

#### Answer

$= \frac{27n^{2}}{28}$

#### Work Step by Step

We first multiply the numerators and the denominators of the fractions by each other. Then, we simplify the fractions to obtain: $(\frac{6n}{7})(\frac{9n}{8})$ $= \frac{6n(9n)}{7(8)}$ $= \frac{54n^{2}}{56}$ $= \frac{27n^{2}}{28}$

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