Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 2 - Real Numbers - Chapter 2 Review Problem Set - Page 88: 17

Answer

$= \frac{1}{15}$

Work Step by Step

We first create a common denominator, and then we add the numerators together to obtain: $\frac{2}{3} + \frac{-3}{5}$ $= \frac{2(5)}{15} + \frac{-3(3)}{15}$ $= \frac{10}{15} + \frac{-9}{15}$ $= \frac{10}{15} - \frac{9}{15}$ $= \frac{1}{15}$
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