## Elementary Algebra

Let the first odd number be $x$, the second odd number be $x+2$ and the third odd number be $x+4$. (We can do this because odd numbers are two apart, so we know that if the first odd number is x, the following odd numbers will be 2 and 4 greater than x, respectively.) Since the sum of three numbers is $147$, we obtain: $x+(x+2)+(x+4)=147$ $x+x+2+x+4=147$ $3x+6=147$ $3x=147-6$ $3x=141$ $x=47$ Since $x$ is 47, $(x+2)$ is 49, and $(x+4)$ is 51.