Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Appendix - Extra Word Problems - Page 523: 9



Work Step by Step

Let the first odd number be $x$, the second odd number be $x+2$ and the third odd number be $x+4$. (We can do this because odd numbers are two apart, so we know that if the first odd number is x, the following odd numbers will be 2 and 4 greater than x, respectively.) Since the sum of three numbers is $147$, we obtain: $x+(x+2)+(x+4)=147$ $x+x+2+x+4=147$ $3x+6=147$ $3x=147-6$ $3x=141$ $x=47$ Since $x$ is 47, $(x+2)$ is 49, and $(x+4)$ is 51.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.