## Elementary Algebra

Let the first unknown whole number be $x$, let the second unknown whole number be $x+1$ and let the third unknown whole number be $x+2$. Since the numbers are consecutive, they differ by 1. Since the largest number is subtracted from the sum of the other two numbers to get a result of 48, we obtain: $(x+x+1)-(x+2)=48$ $(2x+1)-(x+2)=48$ $2x+1-x-2=48$ $x-1=48$ $x=48+1$ $x=49$ Therefore, the first number is $49$, the second number is $49+1=50$, and the third number is $50+1=51$.