#### Answer

49,50,51

#### Work Step by Step

Let the first unknown whole number be $x$, let the second unknown whole number be $x+1$ and let the third unknown whole number be $x+2$. Since the numbers are consecutive, they differ by 1.
Since the largest number is subtracted from the sum of the other two numbers to get a result of 48, we obtain:
$(x+x+1)-(x+2)=48$
$(2x+1)-(x+2)=48$
$2x+1-x-2=48$
$x-1=48$
$x=48+1$
$x=49$
Therefore, the first number is $49$, the second number is $49+1=50$, and the third number is $50+1=51$.