Answer
a) The basis for row-space is of $A$ equal to $\{(1,2,3,4,5)\}$.
b) The basis for column-space of $A$ is equal to $\{(1)\}$ with $m=1$.
Work Step by Step
a) We notice that there is only one row vector which is equivalent to basis of row space of $A$ with $n=5$. So, the basis for row-space is of $A$ equal to $\{(1,2,3,4,5)\}$.
b) We notice that all column entries of $A$ are dependent $\{(1,2,3,4,5)\}$ . So, the basis for column-space of $A$ is equal to $\{(1)\}$ with $m=1$.
