Differential Equations and Linear Algebra (4th Edition)

Published by Pearson
ISBN 10: 0-32196-467-5
ISBN 13: 978-0-32196-467-0

Chapter 4 - Vector Spaces - 4.5 Linear Dependence and Linear Independence - Problems - Page 297: 25

Answer

See below

Work Step by Step

Given $V=R^3\\ v_1=(1,2,3)\\ v_2=(-3,4,5)\\ v_3=(1,-\frac{4}{3},-\frac{5}{3})$ Let $S=span\{v_1,v_2,v_3\}$ We can notice that $0v_1-\frac{1}{3}v_2=0-\frac{1}{3}v_2=-\frac{1}{3}v_2=-\frac{1}{3}(-3,4,5)=(-1,\frac{-4}{3},\frac{5}{3})$ Thus, $S=span\{v_1,v_2,v_3\}=span\{v_1,v_2\}$ Since $v_1,v_2$ are not proportional, $v_1$ and $v_2$ are linearly independent. Hence, $\{v_1,v_2\}$ is a linearly independent set spans $S$.
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