Answer
$4$
Work Step by Step
We know that if $av_1+bv_2=v$, then $a+2b=3,-a+b=3,2a+3b=4$.
Thus $(a+2b)+(-a+b)=3+3\\3b=6\\b=2$
$-a+b=-a+2=3\\a=-1$
And this satisfies the last equation because$2(-1)+3(2)=-2+6=4$
Differential Equations and Linear Algebra (4th Edition)
by Goode, Stephen W.; Annin, Scott A.
Published by
Pearson
ISBN 10:
0-32196-467-5
ISBN 13:
978-0-32196-467-0
Chapter 4 - Vector Spaces - 4.4 Spanning Sets - Problems - Page 283: 37
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