Differential Equations and Linear Algebra (4th Edition)

Published by Pearson
ISBN 10: 0-32196-467-5
ISBN 13: 978-0-32196-467-0

Chapter 4 - Vector Spaces - 4.11 Chapter Review - Additional Problems - Page 336: 20

Answer

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Work Step by Step

We are given $S=\{A \in M_2R:$ A is orthogonal$\}$ Assume that $S=\begin{bmatrix} 0 & 0\\ 0 & 0 \end{bmatrix} \notin S \rightarrow $ We can notice that $S$ is the zero vector $M_2(R)$ and every subspace of a vector space $S$ contain the zero vector of $S$. Hence $S$ is not a subspace of $M_2R$
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