Differential Equations and Linear Algebra (4th Edition)

Published by Pearson
ISBN 10: 0-32196-467-5
ISBN 13: 978-0-32196-467-0

Chapter 2 - Matrices and Systems of Linear Equations - 2.9 Chapter Review - Additional Problems - Page 192: 5

Answer

$AB=\begin{pmatrix} 16 & 8\\ 6 & -17 \end{pmatrix}$ $tr(AB)=\begin{pmatrix} 16 & 6\\ 8 &-17 \end{pmatrix}$

Work Step by Step

$AB$ $=\begin{pmatrix} -2 & 4 & 2 & 6\\ -1 & -1 & 5 & 0 \end{pmatrix}\begin{pmatrix} -3 & 0\\ 2 & 2\\ 1 & -3\\ 0 & 1 \end{pmatrix}$ $=\begin{pmatrix} 16 & 8\\ 6 & -17 \end{pmatrix}$ $tr(AB)=\begin{pmatrix} 16 & 6\\ 8 &-17 \end{pmatrix}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.