Answer
See below
Work Step by Step
Let $A$ be an $m \times n$ matrix and let $B$ be an $p\times n$ matrix.
Then, (j,i) entry of $AB^T=\sum^n_{k=0}a_{jk}b^T_{ki}=\sum^n_{k=0}a_{jk}b+{ik}=\sum^n_{k=0}b_{ik}a_{kj}^T$
Hence, the (i,j)-entries of $(AB^T)^T$ and $BA^T$ are the same.
