College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.3 - Integer Exponents and Scientific Notation - P.3 Exercises: 14

Answer

a. $-2^{-3}.(-2)^{0} = -\frac{1}{8} $ b. $-2^{3}.(-2)^{0} = -8 $ c. $(\frac{-2}{3})^{-3} = -\frac{27}{8}$

Work Step by Step

a. $-2^{-3}.(-2)^{0} = -\frac{1}{2^{3}} \times 1 = -\frac{1}{2\times2\times2} = -\frac{1}{8} $ b. $-2^{3}.(-2)^{0} = -(2\times2\times2)\times1 = -8 $ c. $(\frac{-2}{3})^{-3} = \frac{1}{(\frac{-2}{3})^{3}} = (\frac{-3}{2})^{3} = (-\frac{3}{2})\times(-\frac{3}{2})\times(-\frac{3}{2}) = -\frac{27}{8}$
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