College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.3 - Integer Exponents and Scientific Notation - P.3 Exercises - Page 23: 10


No, $(x^{2})^3 \ne x^{5}$ No, $(2x^{4})^{3}\ne(2x^{12})$

Work Step by Step

When we raise a power to a new power we multiply the exponents, So, $(x^{2})^3 = x^{2\times3} = x^{6}$ which is not equal to $x^{5}$ B. $(2x^{4})^{3}=(2^{3}x^{4\times3})=(8x^{12})$ which is not equal to $(2x^{12})$
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