College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.3 - Integer Exponents and Scientific Notation - P.3 Exercises: 13

Answer

a. $(\frac{5}{3})^{0}.2^{-1} = \frac{1}{2}$ b. $\frac{2^{-3}}{3^{0}} = \frac{1}{8}$ c. $(\frac{1}{4})^{-2} = 16 $

Work Step by Step

a. $(\frac{5}{3})^{0}.2^{-1}$ = $1\times\frac{1}{2^{1}}$ = $\frac{1}{2}$ b. $\frac{2^{-3}}{3^{0}} = \frac{1}{2^{3}\times3^{0}} = \frac{1}{8\times1} = \frac{1}{8}$ c. $(\frac{1}{4})^{-2} = (\frac{1}{(\frac{1}{4})^{2}}) = (\frac{4}{1})^{2} = 16 $
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