## College Algebra 7th Edition

(a) $\frac{8}{3}$ (b) 3
(a) $\frac{2}{\frac{2}{3}}-\frac{\frac{2}{3}}{2}=2\cdot\frac{3}{2}-\frac{2}{3}\cdot\frac{1}{2}=3-\frac{1}{3}=\frac{9}{3}-\frac{1}{3}=\frac{8}{3}$ (b) $\frac{\frac{2}{5}+\frac{1}{2}}{\frac{1}{10}+\frac{3}{15}}=\frac{\frac{2}{5}+\frac{1}{2}}{\frac{1}{10}+\frac{1}{5}}=\frac{\frac{2}{5}+\frac{1}{2}}{\frac{1}{10}+\frac{1}{5}}$ * $\frac{10}{10}=\frac{\frac{2*10}{5}+\frac{1*10}{2}}{\frac{1*10}{10}+\frac{1*10}{5}}=\frac{4+5}{1+2}=\frac{9}{3}=3$