College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.2 - Real Numbers - P.2 Exercises: 29

Answer

Answer: $\frac{17}{30}$

Work Step by Step

$\frac{3}{10}+\frac{4}{15}$ To solve this we need to find the LCM of the denominator of both the fractions. I.e. LCM of 10 & 15 is 30. So now, Multiplay both fractions to make denominator as the LCM of both the denominators. $\frac{3\times3}{10\times3}+\frac{4\times2}{15\times2}$ = $\frac{9}{30}+\frac{8}{30}$ = $\frac{9+8}{30}$ = $\frac{17}{30}$
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