## College Algebra 7th Edition

(a) 3 (b) $\frac{13}{20}$
(a) $\frac{2}{3}(6-\frac{3}{2})=\frac{2}{3}*6-\frac{2}{3}*\frac{3}{2}=4-1=3$ (b) $(3+\frac{1}{4})(1-\frac{4}{5})=(\frac{3*4}{1*4}+\frac{1}{4})(\frac{1*5}{1*5}-\frac{4}{5})=(\frac{12}{4}+\frac{1}{4})(\frac{5}{5}-\frac{4}{5})=(\frac{13}{4})(\frac{1}{5})=\frac{13}{20}$