## College Algebra 7th Edition

(a) $\frac{3}{2}$ (b) $\frac{1}{6}$
We find common denominators and reduce: (a) $\displaystyle \frac{5}{6}+\frac{2}{3}=\frac{5}{6}+\frac{4}{6}=\frac{9}{6}=\frac{3}{2}$ (b) $\displaystyle \frac{5}{6}-\frac{2}{3}=\frac{5}{6}-\frac{4}{6}=\frac{1}{6}$