## College Algebra 7th Edition

(a) $\frac{9}{2}$ (b) $\frac{25}{32}$
(a) We multiply across and reduce: $\displaystyle \frac{15}{8}*\displaystyle \frac{12}{5}=\frac{15 * 12}{8*5}=\frac{3*3}{2*1}=\frac{9}{2}$ (b) We flip the second fraction, multiply, and reduce: $\displaystyle \frac{15}{8}\div\frac{12}{5}=\frac{15*5}{8*12}=\frac{5*5}{8*4}=\frac{25}{32}$