College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Chapter P Review - Exercises - Page 76: 29

Answer

$\frac{1}{6}$

Work Step by Step

We convert the negative exponent to a fraction and the fraction exponent to a root: $216^{-1/3}=\displaystyle \frac{1}{216^{1/3}}=\frac{1}{\sqrt[3]{216}}=\frac{1}{6}$
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