Answer
$2795$ is the 48th term of the sequence.
Work Step by Step
RECALL:
The $n^{th}$ $a_n$ of an arithmetic sequence is given by the formula:
$a_n = a + d(n-1)$
where
$a$ = first term
$d$ = common difference
The sequence has $a=3500$ and $d=-15$. Substituting these tot he formula above gives:
$a_n=3500 + (-15)(n-1)
\\a_n=3500-15(n-1)$
The $n^{th}$ term is $2795$. To know the value of $n$, substitute $2795$ to $a_n$ to obtain:
$a_n = 3500-15(n-1)
\\2795=3500-15(n-1)
\\2795 - 3500 = -15(n-1)
\\-705 = -15(n-1)
\\\dfrac{-705}{-15}=\dfrac{-15(n-1)}{-15}
\\47=n-1
\\47+1 = n-1+1
\\48=n$
Thus, $2795$ is the 48th term of the sequence.