## College Algebra 7th Edition

Published by Brooks Cole

# Chapter 8, Sequences and Series - Section 8.2 - Arithmetic Sequences - 8.2 Exercises - Page 607: 43

#### Answer

$d=s$ $a_5=2+4s$ The $n^{th}$ term is given by: $a_n = 2+s(n-1)$ $a_{100} = 2+99s$

#### Work Step by Step

The sequence is arithmetic so the terms have a common difference. The common difference $d$ can be found by subtracting any term to the next term in the sequence. Thus, $d=(2+s)-2 \\d=2+s-2 \\d=s$ The fifth term $a_5$ can be found by adding the common difference $s$ to the fourth term. The fourth term of the sequence is $2+3s$. Thus, $a_5 = 2+3s+s \\a_5=2+4s$ The $n^{th}$ term $a_n$ of an arithmetic sequence is given by the formula $a_n = a+d(n-1)$ where $a$ = first term and $d$ = common difference. The sequence has $a=2$ and $d=s$. Thus, the $n^{th}$ term is given by: $a_n = 2+s(n-1)$ Substituting 100 to $n$ gives the 100th term as: $a_{100} = 2+s(100-1) \\a_{100} = 2+s(99) \\a_{100} = 2+99s$

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