Answer
vertical, $(0,\pm a)$, $c=\sqrt{a^2+b^2}$
$(0,\pm 4)$,$(0,\pm 5)$
Work Step by Step
The graph of $\frac{y^2}{a^2}-\frac{x^2}{b^2}=1$ with $a,b\gt 0$ is a hyperbola with vertical transverse axis that has vertices $(0,\pm a)$ and foci $(0,\pm c)$, where $c=\sqrt{a^2+b^2}$.
Hence the graph of $\frac{y^2}{3^2}-\frac{y^2}{3^2}=1$ is a hyperbola that has vertices $(0,\pm 4)$ and foci $(0,\pm 5)$, where $c=\sqrt{4^2+3^2}=5$.
