Answer
(a) Vertices: $(0,±1)$
Foci: $(0,±\sqrt {26})$
Asymptotes:
$y=±\frac{1}{5}x~~$ (Black lines)
(b) Length of the tranverse axis:
$2a=2$
Work Step by Step
Hyperbola with vertical transverse axis:
$\frac{y^2}{a^2}-\frac{x^2}{b^2}=1$
$\frac{y^2}{1}-\frac{x^2}{25}=1$
$a^2=1$
$a=1$
Vertices: $(0,±a)=(0,±1)$
$b^2=26$
$b=5$
$c^2=a^2+b^2=25+1=26$
$c=\sqrt {26}$
Foci: $(0,±c)=(0,±\sqrt {26})$
Asymptotes:
$y=±\frac{a}{b}x$
$y=±\frac{1}{5}x$
Length of the tranverse axis:
$2a=2$
