Answer
horizontal, $(\pm a,0)$, $c=\sqrt{a^2+b^2}$.
$(\pm4,0)$, $(\pm 5,0)$
Work Step by Step
The graph of $\frac{x^2}{a^2}-\frac{y^2}{b^2}=1$ with $a,b\gt 0$ is a hyperbola with horizontal transverse axis that has vertices $(\pm a,0)$ and foci $(\pm c,0)$, where $c=\sqrt{a^2+b^2}$.
Hence the graph of $\frac{x^2}{4^2}-\frac{y^2}{3^2}=1$ is a hyperbola that has vertices $(\pm 4,0)$ and foci $(\pm 5,0)$, where $c=\sqrt{4^2+3^2}=5$.
