College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 7, Conic Sections - Section 7.1 - Parabolas - 7.1 Exercises - Page 555: 55

Answer

$y^2=x$

Work Step by Step

Equation of a parabola with horizontal axis: $y^2=4px$ The parabola passes through the point $(4,-2)$. Let' use the point $(4,-2)$: $(-2)^2=4p(4)$ $4=16p$ $p=\frac{4}{16}$ $p=\frac{1}{4}$ $y^2=4px$ $y^2=4(\frac{1}{4})x$ $y^2=x$
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