College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 7, Conic Sections - Section 7.1 - Parabolas - 7.1 Exercises - Page 555: 54

Answer

$x^2=10y$

Work Step by Step

Equation of a parabola with vertical axis: $x^2=4py$ The parabola passes through the point $(5,p)$. Let' use the point $(5,p)$: $5^2=4p(p)$ $25=4p^2$ $p^2=\frac{25}{4}$ $p=±\frac{5}{2}$ The parabola opens upwards. Focus is on the positive y-axis. So, $p$ is also positive: $p=\frac{5}{2}$ $x^2=4py$ $x^2=4(\frac{5}{2})y$ $x^2=10x$
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