Answer
$x^2=-40y$
Work Step by Step
Opens downwards. It is a parabola with vertical axis.
Focus: $F(0,p)$
Vertex: $V(0,0)$
$p$ is a negative number because the focus is on the negative y-axis. The vertex is above the focus.
Distance between the focus and the vertex: $0-p=-p$
$-p=10$
$p=-10$
Equation: $x^2=4py$
$x^2=4(-10)y$
$x^2=-40y$