Answer
$0$, not invertible
Work Step by Step
We know that for a matrix
$
\left[\begin{array}{rrr}
a & b & c \\
d &e & f \\
g &h & i \\
\end{array} \right]
$
the determinant is given as:
$D=a(ei-fh)-b(di-fg)+c(dh-eg).$
Thus, we have:
$D=1(0\cdot2-8\cdot2)-3(2\cdot2-8\cdot0)+7(2\cdot2-0\cdot0)=1(-16)-3(4)+7(4)=0.$
The determinant is $0$, so the matrix is not invertible.