## College Algebra 7th Edition

Yes an inverse exists, $det(A) = 4$
Let us extend the matrix and use Sarrus's rule. $$\begin{matrix} 2 & 1 & 0 &2 & 1 \\ 0 & -2 & 4&0 & -2 \\ 0 & 1 & -3 &0 & 1 \end{matrix}$$ $2*-2*-3-8 = 4$