College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 6, Matrices and Determinants - Section 6.3 - Inverses of Matrices and Matrix Equations - 6.3 Exercises - Page 523: 3

Answer

See below.

Work Step by Step

We multiply the matrices as follows: $AB=\left[\begin{array}{c c} 4\cdot2+1\cdot(-7)& 4\cdot(-1)+1\cdot4\\ 7\cdot2+2\cdot(-7)& 7\cdot(-1)+2\cdot4\end{array} \right]=\left[\begin{array}{c c} 1& 0\\ 0& 1\end{array} \right]$ $BA=\left[\begin{array}{c c} 2\cdot4+(-1)\cdot7& 2\cdot1+(-1)\cdot2\\ (-7)\cdot4+4\cdot7& (-7)\cdot1+4\cdot2\end{array} \right]=\left[\begin{array}{c c} 1& 0\\ 0& 1\end{array} \right]$ Hence we verified what we had to.
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