Answer
See below
Work Step by Step
We find the determinant $(ad-bc)$
$2-5/3=1/3$
Use the formula
\[
M=\frac{1}{ad-bc}
\left[ {\begin{array}{cc}
d &-b \\
-c & a \\
\end{array} } \right]
\]
to get
\[
M= 3
\left[ {\begin{array}{cc}
4 & -1/3 \\
-5 & 1/2 \\
\end{array} } \right]
\]
or \[
M=
\left[ {\begin{array}{cc}
12 & -1 \\
-15 & 3/2 \\
\end{array} } \right]
\]