## College Algebra 7th Edition

We find the determinant $3*-3+10 = 1$ Use the formula $M=\frac{1}{ad-bc} \left[ {\begin{array}{cc} d &-b \\ -c & a \\ \end{array} } \right]$ to get $M= \left[ {\begin{array}{cc} 3 & 5 \\ -2 & -3 \\ \end{array} } \right]$