## College Algebra 7th Edition

$\dfrac{A}{x-3}+\dfrac{Bx+C}{x^2+4}$
Simplify $\dfrac{x^2}{(x-3)(x^2+4)}$ into partial fraction decomposition. Here, $x^2+4$ can not be factorized. The decomposition will be written in the linear function of $x$. Applying the partial fraction decomposition rule. $\dfrac{x^2}{(x-3)(x^2+4)}=\dfrac{A}{x-3}+\dfrac{Bx+C}{x^2+4}$