Answer
$\dfrac{A}{x-3}+\dfrac{Bx+C}{x^2+4}$
Work Step by Step
Simplify $\dfrac{x^2}{(x-3)(x^2+4)}$ into partial fraction decomposition.
Here, $x^2+4$ can not be factorized.
The decomposition will be written in the linear function of $x$.
Applying the partial fraction decomposition rule.
$\dfrac{x^2}{(x-3)(x^2+4)}=\dfrac{A}{x-3}+\dfrac{Bx+C}{x^2+4}$
