Answer
$\dfrac{A}{x+4}+\dfrac{B}{x-1}$
Work Step by Step
Simplify $\dfrac{x}{x^2+3x-4}$ into partial fraction decomposition.
This can be written as:
$\dfrac{x}{x^2+3x-4}=\dfrac{x}{(x+4)(x-1)}$
Applying the partial fraction decomposition rule.
$\dfrac{x}{(x+4)(x-1)}=\dfrac{A}{x+4}+\dfrac{B}{x-1}$
