Answer
$\dfrac{A}{x-2}+\dfrac{B}{(x-2)^2}+\dfrac{C}{x+4}$
Work Step by Step
Simplify $\dfrac{x^2-3x+5}{(x-2)^2(x+4)}$ into partial fraction decomposition.
Applying the partial fraction decomposition rule.
$\dfrac{x^2-3x+5}{(x-2)^2(x+4)}=\dfrac{A}{x-2}+\dfrac{B}{(x-2)^2}+\dfrac{C}{x+4}$