College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 5, Systems of Equations and Inequalities - Chapter 5 Review - Exercises - Page 479: 9

Answer

$(16/7,-14/3)$

Work Step by Step

If we add twice the first equation to the second one, we get: $7x=16\\x=16/7$ Plugging this back into the first equation, we get: $3(16/7)+4/y=6\\48/7+4/y=6\\-6/7=4/y\\y/4=-7/6\\y=-14/3$ Hence, the solution is: $(16/7,-14/3)$
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